(x^3/3y)/(-x^4/9y^2)

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Solution for (x^3/3y)/(-x^4/9y^2) equation: 


D( x )

(((-x)^4)/9)*y^2 = 0

(((-x)^4)/9)*y^2 = 0

(((-x)^4)/9)*y^2 = 0

1/9*x^4*y^2 = 0 // : 1/9*y^2

x^4 = 0

x = 0

x in (-oo:0) U (0:+oo)

(((x^3)/3)*y)/((((-x)^4)/9)*y^2) = 0

3*x^-1*y^-1 = 0 // : 3*y^-1

x^-1 = 0

x naleu017Cy do O

x belongs to the empty set

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